Arial , Lab 11 Gravimetric Analysis Table 1: Data and Observations Mass 2.0g CaC

Question

Arial , Lab 11 Gravimetric Analysis Table 1: Data and Observations Mass 2.0g CaClzi 2.59 2.39 Filter Paper 32 Watch Glass 1.8g (the precipitate resembled chalk, especially chalk that was wet and later dried) Precipitate Table 2: 24 Hour CaCl2 Observations 2.5 g (the weigh boat weight 2.2 g and the initial mass of the CaCl2 was 2.0 g) After the 24-hour period, the sample of CaCl2 increased in mass by 0.5 g. There was evidence of precipitation or water particles in the weigh boat with the CaCl. Also, some pieces appeared to be partially soggy 24 hour CaCl - 1278 Words ELGOEEDFocus - _ 15

Explanation / Answer

The first thing to do is to put the chemical equation

CaCl2 + K2CO3 === CaCO3 + 2 KCl

1 mole of CaCl2 reacts with mole of K2CO3

calculate the number of moles of each reactant

molar mass of CaCl2 is 111 g/mol

molar mass of K2CO3 is 138.205 g/mol

moles of CaCl2 is 2 / 111 = 0.018

moles of K2CO3 is 2.5 / 138.205 = 0.018

there is equal amount of moles for the reactants

according to these values theoretically you should be able to produce 0.018 moles of CaCO3

you actually got 1.8 grams of precipitate, the molar mass of CaCO3 is 100.0869

moles = mass / molar mass = 1.8 / 100.0869 = 0.0179 moles

percent yiel is

actual yield / theoretical yield * 100

0.0179 / 0.018 * 100 = 99.44 %

to answer the other questions more info should be provided...

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.