Argon will sit in the bottom of your lungs and suffocate youif you breathe it. T

Question

Argon will sit in the bottom of your lungs and suffocate youif you breathe it. This implies that Ar is denser thanair. If Ar gas has a 10% smaller volume than it would if itwere a perfect as at STP A)    What is the compression factor, definedas Vm/Vom where Vom is the perfect gas volumeper mole? B)  What is it's (imperfect) molar volume Vm? HINT: Find that Vm is 22.02 L/mol. Will rate ASAP!!! Argon will sit in the bottom of your lungs and suffocate youif you breathe it. This implies that Ar is denser thanair. If Ar gas has a 10% smaller volume than it would if itwere a perfect as at STP A)    What is the compression factor, definedas Vm/Vom where Vom is the perfect gas volumeper mole? B)  What is it's (imperfect) molar volume Vm? HINT: Find that Vm is 22.02 L/mol. Will rate ASAP!!!

Explanation / Answer

Start with the compressible form of the ideal gas law: P V = z n RT, where z is the compressibility factor.
If the gas were ideal (z = 1) you can solve for the molarvolume at STP where V/n = z R T/P = R T / P = 24.47 L/mol
If it actually has a 10% smaller volume than "expected" thanit's compressibility factor would be .90 (you woul multiply the idealpressure by .90 to get the actual one)
B) Well, we know that the ideal volume is V0m = 24.47 L/mol So, Vm = z V0m = .90 (24.47 L/mol) = 22.02 L/mol You could have also done V / n = z R T / P with z = .90 andgotten the same answer
Hope that helps

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