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For each of the following problems, write the governing chemical reaction and st

ID: 1027835 • Letter: F

Question

For each of the following problems, write the governing chemical reaction and state its equilibrium constant. Additionally, clearly state your assumption, and check it!
Calculate the pH of a solution that results from mixing 22.0 mL 0.15 M of acetic acid with 17 mL of 0.15 M NaOH.
Please show how to use dillusion process and ICE table in order to solve this problem! For each of the following problems, write the governing chemical reaction and state its equilibrium constant. Additionally, clearly state your assumption, and check it!
Calculate the pH of a solution that results from mixing 22.0 mL 0.15 M of acetic acid with 17 mL of 0.15 M NaOH.
Please show how to use dillusion process and ICE table in order to solve this problem! For each of the following problems, write the governing chemical reaction and state its equilibrium constant. Additionally, clearly state your assumption, and check it!
Calculate the pH of a solution that results from mixing 22.0 mL 0.15 M of acetic acid with 17 mL of 0.15 M NaOH.
Please show how to use dillusion process and ICE table in order to solve this problem! For each of the following problems, write the governing chemical reaction and state its equilibrium constant. Additionally, clearly state your assumption, and check it!
Calculate the pH of a solution that results from mixing 22.0 mL 0.15 M of acetic acid with 17 mL of 0.15 M NaOH.
Please show how to use dillusion process and ICE table in order to solve this problem!

Explanation / Answer

millimoles of acetic acid = 22 x 0.15 = 3.3

millimoles of NaOH = 17 x 0.15 = 2.55

CH3COOH   +   NaOH    ----------------> CH3COO-   +   H2O

3.3                 2.55                                       0                 0   -----------> I

-2.55               - 2.55                                  +2.55                 ------------> C

0.75                 0.0                                      2.55                 ----------->   E

pH = pKa + log [salt / acid]

     = 4.74 + log [2.55 / 0.75]

pH = 5.27

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