0.150L ressure of Ne?0.5mol 0.75mol g of Ne and 10.0 g Ar have a total pressure

Question

0.150L ressure of Ne?0.5mol 0.75mol g of Ne and 10.0 g Ar have a total pressure of 1.6 atm. What is the mol /0.75mol 10g x Imot 0.5 A) 1.1 atm B) 0.80 atm C) 0.54 atm D) 0.40 atm 20-180 10q x Imo 39.95 0.25 ate the change in internal energy (AE) for a system that is absorbing 35.8 kJ of heat C a59 1.0IATM and is expanding from 8.00 to 16.0 L in volume at 2.00 atm. A) +51.8 k B) -15.8 k.J C)-16.6 k D) +34.2 kJ If CO2 and NH3 are allowed to effuse through a porous membrane under identical conditions, the rate of effusion for NH3 will be . times that of CO2. A) 0.39 B) 0.62 C) 1.6 D) 2.6

Explanation / Answer

Change in internal energy , E = q – PV (expanding the volume)

Or E = q + W

q is the amount of heat absorbed, 35.8 kJ

p is the pressure in atm , 2 atm

V is change in volume, 16-8 = 8 L

W is the workdone

here, PV = 16 atm L

converting atm L into J by multiplying with 101.33 because given in heat in kJ

16 atm L = 16 x 101.33 =1621.28 J or 1.621 kJ

Now, E = 35.8 kJ – 1.621 kJ =34.179

rounding off to 34.2 kJ

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