1. How many moles of N2 are contained in a 5000 mL tank at 428Kelvin and 2128 to
ID: 1027274 • Letter: 1
Question
1. How many moles of N2 are contained in a 5000 mL tank at 428Kelvin and 2128 torr? A) 0.399 moles B) 1.10 moles C) 2.51 moles D) 0.455 moles E) 0.289 moles Hint PV nRT 62-y borr. 2. What is the molar mass (g/mole) of a 0.334 g sample of a substance that occupies 0.109 L 125 Celsius and 1072 mmHg. w RT PV A) 160. B) 38.0 C) 71.0 D) 254 E) 32.0 Mo! .SJ lculate the molality of a solution formed by dissolving 3.80 g of NaCI in 300.0 mL of wa Density of water- 1.0 g/ml) A) 0.254 m B) 0.394 m C) 0.2.17 x 103 m D) 0.0650 m E) 0.217 m 4.Choose the aqueous solution below with the lowest freezing point. These are all solutions nonvolatile solutes and you should assume ideal van't Hoff factors where applicable. A) 0.75 m KF B) 0.75 m CCl C) 0.75 m HCN D) 0.75 m Li2O E) 0.75 m KNO2 5. Given the following rate law, how does the rate of reaction change if the concentration ot doubled? Rate-k 2 A) The rate of reaction will increase by a factor of 2.Explanation / Answer
Answer (1)
this will be solved by using ideak gas law PV=nRT or n= PV/RT
here P = pressure = 2128 torr
V= volume = 5000 mL=5L
R=gas constant = 62.4 torr.L/mol.K
T=temperature = 428 K
using the values in the eqauation
n= 2128*5/428*62.4= 0.398 moles
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