A mixture of 1-heptyne, 2-heptyne, and 3-heptyne was hydrogenated in the presenc

Question

A mixture of 1-heptyne, 2-heptyne, and 3-heptyne was hydrogenated in the presence of a platinum catalyst until hydrogen uptake ceased. If one assumes that the hydrogenation went to completion, how many distinct seven-carbon hydrocarbons were produced?

A mixture of 1-heptyne, 2-heptyne, and 3-heptyne was hydrogenated in the presence of a platinum catalyst until hydrogen uptake ceased. If one assumes that the hydrogenation went to completion, how many distinct seven-carbon hydrocarbons were produced?

I know the answer is one, but I don't understand what the question is asking. Can someone please explain in simple terms. Thanks.

Explanation / Answer

The correct answer will be 1

Reason: The platinum catalyst will reduce the ethyne to ethane by the addition of H2 to the structures

1-heptyne on treatment will no longer contain the double bond and will contain the straight 7 carbon chain as the output

Similarly 2-heptyne and 3-heptyne will also be reduced to n-heptane, which is the only possible product, since there is number priority this time because the triple bond is reduced to single bond by the reaction with Pt Catalyst

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