You\'ve just joined a new research lab and have been tasked with determining the

Question

You've just joined a new research lab and have been tasked with determining the accuracy of the lab's pipetors-unfortunately you're out of double deionized water so the only water you have is San Marcos' finest which you cannot imagine what the density of that is so you've opted not to use it for this endeavor. After browsing around the lab you find that you do have some 100% (density 0.792 g/mL) and you decided that you want to simply use that to determine the percent error of your P1000. Using your P1000 you collect 1 mL of methanol and determine that it has a mass 0.895 g (your scale is calibrated accurately). What is the percent error of your P1000?

Explanation / Answer

Percent error = Experimental value - Actual value   * 100

                                    Actual value

                        = (0.895 - 0.792) / ( 0.792) * 100

                        = 13 %

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