Name the formulas: [Ag(NH 3 ) 2 ]Cl : __________ __________ argentate __________

Question

Name the formulas:

[Ag(NH3)2]Cl : __________ __________ argentate __________

[Pt(CO)2(en)2]I2 : __________ carbonyl __________ ethylenediamineplatinate __________ iodide

K2[CoCl4] : potassium tetrachloro __________ __________

[Fe(en)3]N : __________ __________ __________ __________ __________

[Al(OH)4]- : tetra __________ __________ ion

Fe(CO)5 : penta __________ __________ (0)

[Cr(H2O)2(C2O4)2]2+ : __________ __________ __________ __________ __________ __________ ion

I'm having a difficult time understanding how do this problem. If anyone can help me figure out how I get the answers, I'd greatly appreciate it. Will rate. Thank you so much!

Explanation / Answer

Solution:- (1) In this complex Cl is present out of the coordination sphere so the charge on the sphere is positive and so we use the suffix -ate to the name of the central metal. Name of the ligands present in the sphere are written alphabatically and prefixes like di, tri, tetra etc are used to represent how many times a particular ligand is present. the ion which is present outside the coordination sphere is written noramly like Cl is written as chloride. In this complex, Ag is present in +1 state which is written next to Argentate in the bracket in roman numerals. The complete name will be..

diamineargentate(I)chloride

(2) This one is also like the first one means it also has positive charge on the complex. Iodine is present outside the sphere so it will be written at last. Central atom is Platinium and it is in +2 state since the charges for CO and en are zero and +2 is because of two iodide ions. we use the suffix -ate for the central metal, Pt and roman numeral (II) is used for this as it is in +2 state. CO is carbonyl and en is ethylenediamine. c comes first than e so in alphabatic order carbonyl is written before ethylenediamine. Since there are two en in the complex so prefix -bis is used for it. Prefix -di is not used here since the ligand already have di in it's name. The complete name is..

dicarbonylbis(ethylenediamine)platinate(II) iodide.

(3) For this type of complexes first we write the name of the metal present outside the coordination sphere. Then the name of the ligand along with its prefix di, tri etc is written and finally the name of the central metal with suffix- ate and roman numeral is written. The name will be..

potassium tetrachlorocobaltate(II).

(4) There are three en in it so the prefix -tris is used for it and Fe is in +3 state because of one N present outside the coordination sphere. So, Fe will be written as ferrate(III) and N would be written as Nitride. The complete name will be..

tris(ethylenediamine)ferrate(III) nitride.

(5) When the complex has negative charge then we use the suffix -ion in the enidng for the central metal. OH is written as hydroxo. Since there are four OH so it is written as tetrahydroxo. Suffix -ate is used for the metal ion.The name is written as...

tetrahydroxoaluminate(III) ion.

(6) In this complex iron is in 0 oxidation state. So, in the parenthesis 0 is written where we write the roman numerals to represent the oxidation state of the central metal. There we have five carbonyl ligands so prefix -penta is used for it. Since Fe is in 0 state so we will write Iron for it and the complete name will be..

pentacarbonyliron(o)

(7) Here we have all the ligands in the coordination sphere an no ligand is there outside the sphere so we write the suffix -ion in the ending. Ligands are written in alphabatic order. H2O is aqua and C2O4 is oxalato. there are two ligands of each type so prefix -di is used for both of these. Oxalate ion has -2 charge. Since there are two oxalato ligands and +2 charge is on the complex so the oxidation state of Cr would be +2 and the complete name will be..

diaquadioxalatochromate(II) ion.

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