1 A sample of an unknown copper complex is dissolved in water and prepared for t

Question

1 A sample of an unknown copper complex is dissolved in water and prepared for titration by the addition of methyl orange indicator. The sample is titrated with 0.485 M HCl, and requires 24.37 mL to reach the endpoint. a. 1 NH3 (aq) + 1 HCl (aq)---> 1NH4Cl (aq) b. How many grams of NH3 were in sample? Report your answer with ppth precision. 0.02437L X 0.485 mol/L=0.01182 moles HCL=0.01182 moles NH3 0.01182 moles NH3 X 17.03g/1mol= 0.2013 gNH3= 0.201 g c. The mass of the sample used was 0.9863g. what is the mass of ammonia in the sample?

Explanation / Answer

1 NH3 (aq) + 1 HCl (aq)--->1NH4Cl

in this neutralisation reaction one mole NH3 reacts with one mole HCl to form one mole NH4Cl.

24.37 mL 0.485 M HCl=0.02437*0.485=0.0118 mole HCl

so 0.01182 mole NH3 were in the sample that is 0.01182*17=0.2 gm NH3.

0.9863 g sammple contains 0.2 gm NH3

mass of the ammonia in the sample is 0.2 gm

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