a lab technician makes three successive 10.0ml to 100.0ml dilutions of a 0.97M s

Question

a lab technician makes three successive 10.0ml to 100.0ml dilutions of a 0.97M stock solution of copper chloride, then adds 3.00 ml to a test tube tube initially containing 7.00 ml of an ammonia solution. what is the molarity of copper ions in the test tube? a lab technician makes three successive 10.0ml to 100.0ml dilutions of a 0.97M stock solution of copper chloride, then adds 3.00 ml to a test tube tube initially containing 7.00 ml of an ammonia solution. what is the molarity of copper ions in the test tube? a lab technician makes three successive 10.0ml to 100.0ml dilutions of a 0.97M stock solution of copper chloride, then adds 3.00 ml to a test tube tube initially containing 7.00 ml of an ammonia solution. what is the molarity of copper ions in the test tube?

Explanation / Answer

first three successive dilutions are each 10:1 . So final concentration 0.97/1000 = 9.7*10-4 M

By the addition of 3ml to a test tube initialy containing 7ml of ammonia. So total dilution = 3ml + 7ml = 10ml

After dilution concentration of copper ion = 9.7*10-4 *3/3+7   = 2.91*10-4 M >>>> answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.