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pls i need mechanisms for the 9 Alkyl halides. With 15% Nal-in Acetone SN2 with

ID: 1017251 • Letter: P

Question

pls i need mechanisms for the 9 Alkyl halides.

With 15% Nal-in Acetone SN2 with 1% Ethanolic silver Nitrate SN1

precipitate

50 °C water bath

precipitate

100 °C water bath

1.      2-chlorobutane

NO

NO PPT

No precipitate/cloudiness)

Yes(Cloudiness)

2.      2- bromobutane

NO

Cloudy after

Yes(Cloudiness)

3.      1-chlorobutane

NO

Cloudy after

No precipitate/cloudiness)

No precipitate

4.      1-bromobutane

Yes(immediately)

No precipitate/cloudiness)

Dense precipitate

5.      2-chloro-2-methylpropane

NO

NO PPT

Yes(Cloudiness)

6.     Benzyl chloride

Yes(immediately)

Yes(Cloudiness)

7.     Bromobenzene

NO

NO PPT

No precipitate/cloudiness)

No precipitate/cloudiness

8.     Bromocyclohexane

NO

NO PPT

Yes(Cloudiness)

9.   Bromocyclopentane

NO

Cloudy after

Yes (Dense precipitate)

9 Alkyl halides.

precipitate

50 °C water bath

precipitate

100 °C water bath

1.      2-chlorobutane

NO

NO PPT

No precipitate/cloudiness)

Yes(Cloudiness)

2.      2- bromobutane

NO

Cloudy after

Yes(Cloudiness)

3.      1-chlorobutane

NO

Cloudy after

No precipitate/cloudiness)

No precipitate

4.      1-bromobutane

Yes(immediately)

No precipitate/cloudiness)

Dense precipitate

5.      2-chloro-2-methylpropane

NO

NO PPT

Yes(Cloudiness)

6.     Benzyl chloride

Yes(immediately)

Yes(Cloudiness)

7.     Bromobenzene

NO

NO PPT

No precipitate/cloudiness)

No precipitate/cloudiness

8.     Bromocyclohexane

NO

NO PPT

Yes(Cloudiness)

9.   Bromocyclopentane

NO

Cloudy after

Yes (Dense precipitate)

Explanation / Answer

acetone is especially useful for potassium halides, I think potassium is better surrounded by acetone molecules than sodium ions. The reaction is called Finkelstein reaction and is basically an SN2 exchange. Acetone is the solvent . It dissolves all the reactants and sodium iodide, but other solvents can be used as well provided that it dissolves all the ingredients.

The mechanism is like this:

I(-) ......... R-X --> I-R + X(-)

In the reaction, iodide attacks the alkyl group backwards and as soon as iodide hits the alkyl group, the X is released and the configuration is reversed. This is called as Walden's reconfiguration. For example, an optically active compound like R will be converted to an S.