PLEASE SHOW WORK ON HOW TO REACH THE CORRECT ANSWER. a) Calculate delta G 0\' fo

Question

PLEASE SHOW WORK ON HOW TO REACH THE CORRECT ANSWER.

a) Calculate delta G0' for the isomerization of glucose 6-phosphate to glucose 1-phosphate using the following values:

Glucose 1-Phosphate + HOH ---> Glucose + Pi    (delta G0' = -20.9 kJ/mole)

Glucose 6-Phosphate + HOH ---> Glucose + Pi    (delta G0' = -13.8 kJ/mole)

MY CALCULATIONS: (-13.8) + (+20.9) = +7.1

b) What is the equilibrium ratio of glucose 6-phosphate to glucose 1-phosphate at 25oC?

MY CALCULATIONS: delta G0' = -RTlnKeq =

                                +7.1kJ/mol = (-0.0083145 x 298)lnKeq

                                           Keq = 0.0569

Although I calculate 0.0569, the actual answer is 17.8? I know the only way to get 17.8 is if my delta G0' was -7.1 kJ/mol but according to my calculations I got a positve delta G0'.

PLEASE SHOW WORK ON HOW TO REACH THE CORRECT ANSWER.

Explanation / Answer

your delta Go value is correct

It is asking isomerization from glucose 6-phosphate to glucose 1-phosphate

glucose 6-phosphate --> glucose 1-phosphate

delta Go = (-13.8) + (+20.9) = +7.1

Keq = ratio of glucose 1-phosphate to glucose 6-phosphate

But your 2nd part is wrong

It is asking ratio of ratio of glucose 6-phosphate to glucose 1-phosphate that is not Keq . Answer is 1/Keq

ratio of glucose 6-phosphate to glucose 1-phosphate = 1/0.0569 = 17.8

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