For an enzymatic reaction, if the substrate concentration is equal to 1/5K_m, th

Question

For an enzymatic reaction, if the substrate concentration is equal to 1/5K_m, then the velocity of the reaction will be (express as a percentage of V_max) A enzyme has a V_max of 435 mu M/min. If the initial velocity is 6 mu M/min. If the initial velocity is 6 mu M/min when the substrate concentration is mu M, what is the K_m for this enzyme? An enzyme has a K_m of 171.5 mu M for its substrate. If the initial velocity is 31.0 mu M/min when the substrate concentration is 140.00 mu M, what is the V_mas for this enzyme?

Explanation / Answer

23)

V = Vmax /(1+ Km/[S])

= Vmax / (1 + Km/0.2 Km)

= Vmax / (1 +5)

= 16.7% of Vmax

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