UAU UAC UAA Stop UGA Stop UAG Stop UGG Trp CAU CAC UGU 40. (12 points) Using the

Question

UAU UAC UAA Stop UGA Stop UAG Stop UGG Trp CAU CAC UGU 40. (12 points) Using the following piece of DNA: Tyr UGC (a) Draw the complimentary strand (as the bottom UUA UUG CUU UCA UCG CCU Leu strand) (b) Assuming RNA polymerase reads the top strand Label the template & coding strands (c) draw the transcribed mRNA. (d) Write the amino acid sequence. (e) Give the anti-codon of the 1st two tRNAs (f) From the previous question, replacing the C at the CGU CGC CGA CGG AGU AGC AGA AGG GGU His Leu Pro Arg Gin CUG CAG AAU AAC AUU ACU AUC lle ACC ACA Start ACG GCU GCC GCA Asn 7th position (underlined) with a G would result in what kind of mutation? AUA AUG Start GUU GUC GUA GUG Lys Arg Met or AAG GAU GAC GAA GAG Asp Val Ala Gly 5-TCATGTCTTCGTTATCCTAGTCAT C-3' 3- AGTACAGAAGCAA TAGGATCAG TAG-5 GGA Glu Coding c) 5' G AUG ACU AGG AUA ACG AAG ACA UGA-3 d) Met-Thr-Arg-lle-Thr-Lys-Thr e UAC UGU ) AAG to AAC, Lys to Asn, Missense

Explanation / Answer

f.Base substitution mutations are classified as transitions or transversions. Transitions are mutations in which one pyrimidine (C or T) is substituted by the other and one purine (G or A) is substituted on the complementary strand. The G-C to A-T conversion is a transition mutation, since C becomes T.

Yes it should be A As uracil pairs with Adenine only in RNA.

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.