The velocity of an enzymatic reaction (expressed in n moles x liter^-1 x min^-1)
ID: 1010929 • Letter: T
Question
The velocity of an enzymatic reaction (expressed in n moles x liter^-1 x min^-1) for different concentrations of substrate (S, expressed in moles x liter^-1)) are summarized in the following table. The Hanes-Woolf plot represents [SJ/v (y axis) versus [S] (x axis). Rearrange the Lineweaver-Burk to determine the linear equation for the Hanes-Woolf plot (y = ax + b, with y= [S]/v and x = [S]). What do the intercepts with the [S]/v and the [S] axis, and the slope of the straight line represent? (For example in the Lineweaver-Burk plot, the intercept of the straight line and the y-axis represent 1/Vmax) The Woolf-Augustinsson-Hofstee plot represents v versus v/[S]. Rearrange the Henri-Michaelis-Menten equation to determine the linear equation for the Woolf-Augustinsson-Hofstee plot. What do the intercepts with the v and the v/[S] axis, and the slope of the straight line represent? Compare the numerical values of Km and Vmax calculated from each plot.Explanation / Answer
1) The Hans woolf plot is drawn between [S]/v and [S]
the intercept = Km / Vmax
Slope = 1/Vmax
y = 0.012x + 5E-07
slope = 0.012 = 1/Vmax
Vmax = 83.33
Intecept = 5 X 10^-7 = Km / Vmax
Km = 5 X 10^-7 X Vmax = 5 X 10^-7 X 83.3 = 4.17 X 10^-5
2) Woolf-Augustinsson-Hofstee plot between V and V/S
The line equation will be
y = -4E-05x + 80.00
intercept = Vmax = 80
slope = - Km = 4 X 10^-5
3) the numverical values are different obtained from two graphs however they are comparable
Vmax = 80 and 83.3
Km = almost 4 X 10^-5
[S] V [S]/V 0.0000833 13.8 6.0362E-06 0.00001 16 6.25E-07 0.0000125 19 6.5789E-07 0.0000167 23.6 7.0763E-07 0.00002 26.7 7.4906E-07 0.000025 30.8 8.1169E-07 0.0000333 36.3 9.1736E-07 0.00004 40 0.000001 0.00005 44.4 1.1261E-06 0.00006 48 0.00000125 0.00008 53.4 1.4981E-06 0.0001 57.1 1.7513E-06 0.0002 66.7 2.9985E-06Related Questions
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