The vector position of a 3.90 g particle moving in the xy plane varies in time a

Question

The vector position of a 3.90 g particle moving in the xy plane varies in time according to r1 = (3i + 3j)t + 2j(t^2) where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.00 g particle varies as r2 = 3i 2i(t^2) 6j(t). (a) Determine the vector position of the center of mass at t = 2.40. (b) Determine the linear momentum of the system at t = 2.40. (c) Determine the velocity of the center of mass at t = 2.40. (d) Determine the acceleration of the center of mass at t = 2.40. (e) Determine the net force exerted on the two-particle system at t = 2.40.

Explanation / Answer

The vector position of a 3.90 g particle moving in the xy plane varies in time a

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