1. Calculate the volume (in mL) of 1.0 M H2SO4 stock solution which is needed to
ID: 1010530 • Letter: 1
Question
1. Calculate the volume (in mL) of 1.0 M H2SO4 stock solution which is needed to prepare 150 mL of 0.20 M H2SO4 solution by dilution.
2a. Determine the total charge (in coulombs) passing through a circuit if the average current was 0.568 A over 7.84 minutes.
(b) Determine the number of moles of electrons that passed through the circuit by diving the total charge by Faraday's constant.
3(a) Use the stoichiometry of the cathode reaction to determine the expected number of moles of hydrogen gas, based upon the number of moles of electrons passed through the circuit.
(b) Use the stoichiometry of the anode reaction to determine the expected number of moles of copper oxidized, based upon the number of moles of electrons passed through the circuit.
4(a) If the inital buret reading is 50.00 mL and the final reading is 5.16 mL determine the volume of hydrogen gas produced. (buret is upsidedown)
(b) Determine the pressure of the hydrogen gas collected (in atm) at 298K, given the height of the remaining column of liquid in the buret was measured to be 139 mm and the barometric pressure aas 741.6 mmHg.
You will need to refer to data in table below:
Note: P(H2) = P (barometric) - P (hydrostatic) - P(H2O) and P (hydrostatic) = (height of liquid in buret in mm) / (13.6 mm H2O/ mmHg)
(C) use the ideal gas law to fin the number of moles of hydrogen gas.
5. If the initial mass of the anode was 22.814 g and the final mass was 22.724 g, determine the number of moles of copper oxidized.
6(a) Calculate the 'electrochemical' percent yield of hydrogen gas.
(b) Calcultate the electrochemical percent yield of coppor oxidized.
Temperature (C) Pressure (mmHg) Temperature (C) Pressure (mmHg) 16 13.6 22 19.8 17 14.5 23 21.1 18 15.5 24 22.4 19 16.5 25 23.8 20 17.5 26 25.2 21 18.5 27 26.7Explanation / Answer
1.
This is just a dilution problem
Use dilution formula
M1*V1 = M2*V2
1*V1 = 0.20*150
V1 = 30 mL
Answer: 30 mL
I am allowed to answer only 1 question at a time
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.