-->Magnesium hydroxide, the active ingredient in milk of magnesia, neutralizes s

Question

-->Magnesium hydroxide, the active ingredient in milk of magnesia, neutralizes stomach acid, primarily HCl, according to the reaction: Mg(OH)2(aq)+2HCl(aq)2H2O(l)+MgCl2(aq)

A) What mass of HCl, in grams, is neutralized by a dose of milk of magnesia containing 3.52 g Mg(OH)2?

-->Ammonia can also be synthesized by the reaction:
3H2(g)+N2(g)2NH3(g)

B) What is the theoretical yield of ammonia, in kg, that we can synthesize from 5.37 kg of H2 and 32.6 kg of N2?

-->Ammonia can be synthesized by the reaction: 3 H2(g)+N2(g)2 NH3(g)

C) What is the theoretical yield of ammonia, in kg, that we can synthesize from 5.47 kg of H2 and 31.5 kg of N2?

Explanation / Answer

Mg(OH)2(aq) + 2 HCl(aq) 2 H2O(l) + MgCl2(aq)
1 mole of Mg(OH)2 reacts 2 moles of HCl
58.32 g of Mg(OH)2 reacts with 2 * 36.5 g of HCl
3.52 g of Mg(OH)2 reacts with 2*36.5*3.52/58.32 = 4.406 g of HCl
3H2(g) + N2(g) 2 NH3(g)
3 moles of H2 produces 2 moles of NH3
3*2 g of H2 produces 2*17 g of NH3
5.37 kg of H2 produces 2*17*5.37/6 = 30.43 kg of NH3
1 mole of N2 produces 2 moles of NH3
28 g of N2 produces 2*17 g of NH3
32.6 kg of N2 produces 2*17*32.6/28 = 39.58 kg of NH3
so H2 is limiting reagent amount of NH3 = 30.43 kg
3H2(g) + N2(g) 2 NH3(g)
3 moles of H2 produces 2 moles of NH3
3*2 g of H2 produces 2*17 g of NH3
5.47 kg of H2 produces 2*17*5.47/6 = 30.9967 kg of NH3
1 mole of N2 produces 2 moles of NH3
28 g of N2 produces 2*17 g of NH3
31.5 kg of N2 produces 2*17*31.5/28 = 38.25 kg of NH3
mass of NH3 = 30.9967 kg since H2 is limiting reagent

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