-------> ANSWER: What is the FORMULA for the limiting reagent? __________ ------

Question

-------> ANSWER: What is the FORMULA for the limiting reagent? __________

-------> What is the maximum amount of sodium hydroxide that can be produced? _______ moles

-------> ANSWER: What is the FORMULA for the limiting reagent? __________

-------> What is the maximum amount of carbon dioxide that can be produced? _______ moles

1) For the following reaction, 0.297 moles of sodium are mixed with 0.133 moles of water. sodium (s) + water (l) rightarrow carbon dioxide (g) + hydrogen (g) -------> ANSWER: What is the FORMULA for the limiting reagent? __________ -------> What is the maximum amount of carbon dioxide that can be produced? _______ moles rightarrow sodium hydroxide (aq) + hydrogen (g) -------> ANSWER: What is the FORMULA for the limiting reagent? __________ -------> What is the maximum amount of sodium hydroxide that can be produced? _______ moles 2) For the following reaction, 0.431 moles of carbon monoxide are mixed with 0.534 moles of water. carbon monoxide (g) + water (l)

Explanation / Answer

1) Na(s) + 2H2O(l) ------------> 2NaOH(aq) + H2(g)

Clearly, Na & water reacts in the ratio of 1:2

Thus, for 0.297 moles of Na , moles of watre required = 0.594

Hence the limiting reagent is water (H2O)

Moles of NaOH that can be produced = moles of water reacting = 0.133

2) CO(g) + H2O(l) ----------> CO2(g) + H2(g)

Clearly CO & water reacts in the ratio of 1:1

Thus, for 0.431 moles of CO, 0.431 moles of watre is required

Thus. the limiting reagent is CO

Moles of CO2 produced = moles of CO reacting = 0.431

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