Solubility Product For the following questions, identify the ions comprising the

Question

Solubility Product For the following questions, identify the ions comprising the salt, and then use the expression for the solubility product to perform the necessary calculations. This simple exercise involves the assumptions that you can ignore any complications which might result as a consequence of the basicity or acidity of the ions, ion pairing, complex ion formation, or auto-ionization of water. Calculate the concentration, in mol/L, of a saturated aqueous solution of PbCro4 sp 2.00x10 16 mol/L, 1 pts Submit Answer Tries 0/8 Calculate the solubility, in g/100mL, of PbCro4. g/100 mL. 1 pts Submit Answer Tries 0/8 Calculate the mass of PbC12 (K 1.60x10 5) which will dissolve in 100 ml of water. 1 pts Submit Answer Tries 0/8 Rank the following five salts in order of decreasing solubility, in terms of mass per unit volume. (The most soluble gets rank 1, the least soluble gets rank 5.)

Explanation / Answer

Ksp=[Pb^2+] [CrO4^2-]

Let [Pb^2+ ]=[CrO4^2-]=S

Ksp=2.00*10^-16=S^2

S=1.4*10^-8 M or mol/L

S(g/L)=323.2 g/L *1000ml/L=323.2g/1000 ml=32.3g/100 ml

S=[Pb2+]=[PbCl2]

[Cl-]=2S

Ksp=1.6*10^-5=16*10^-6=[pb2+][Cl-]^2=S*(2S)^2=4S^3

4S^3=16*10^-6

S=1.6*10^-2 mol/L

Molar mass of PbCl2=278.1g/mol

[PbCl2]=278.1g/L=278.1g/1000ml=27.81g/100ml

[PbCl2]=278.1g/L

[Sr3(PO4)2]=

[Sr2+]=3S

Sr3(PO4)2=3Sr2+  +2PO43-

[PO43-]=2S

Ksp=0.1*10^-30=[Sr2+]^3[PO43-]^2=(3S)^3*(2S)^2=108S^5

S=9.3*10^-10 MOL/l=452.8G/1000ML

SIMILARLY CALCULATE FOR

Ca5(PO4)3F<-> 5Ca2+ +3PO43-  +F-

Ksp=[Ca2+]^5[PO43-]^3 [F-]=(5S)^5*(3S)^3*(S)=84375 S^9

S=[Ca5(PO4)3F]

S=1.2*10^-9 mol/L=504.30g/L

[Ag3PO4]=S

Ksp=(3S)^3*S=27S^4=6.67*10^-5 mol/L=418.58g/L

Ca5(PO4)3F>Sr3(PO4)2>[Ag3PO4>PbCrO4>[PbCl2 (decreasing solubility)

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