This is the process by which RNA formed along a DNA template (the genetic inform

Question

This is the process by which RNA formed along a DNA template (the genetic information). This is the first of the two steps needed to transfer genetic information in DNA to protein. From the DNA molecule that you have built with the game pieces, use the strand 3' GGTCCACGTCCA 5' and build the corresponding RNA. Show it to your instructor Draw the DNA and the transcribed RNA here. This is the process of protein (polypeptide) synthesis that occurs on ribosomes as directed by the specific messenger RNA. This is the second of the two steps needed to transfer genetic information in DNA to protein This is done following the genetic code. The RNA is read in triplicates called codons. Use the RNA molecule that you have built. Start at the side of RNA that starts with a G. Match the tRNA amino acid complex to the correct codon. Continue this process until you have completed the polypeptide chain. Show it to your instructor! Draw the polypeptide chain below. What happens if the letters in the DNA are wrong?: Write the RNA sequence based on the DNA sequences. Then determine the amino acid sequence. Refer to the information in the laboratory supplement and write the name of the condition and the consequences of having this condition. Case A DNA sequence: TCT ATA TGC ATG GTC CAG CTC RNA sequence: Amino acid sequence: How is the amino acid sequence of the normal protein different from that of the diseased protein? Condition: Consequences: Case B DNA sequence: GAC TGA GGA CAC CTC TTC AGA RNA sequence: Amino acid sequence: How is the amino acid sequence of the normal protein different from that of the diseased protein? Condition:

Explanation / Answer

Answer:

Based on the given information:

The given DNA sequence is: 3'-CGTCCACGTCCA - 5'

1) The corresponding RNA sequence will be complementry to DNA sequence and instead of Thymine RNA would contain Uracil.

Therefore the corresponding RNA sequence is: 5'-GCAGGUGCAGGU-3'

2) Starting with G determine the polypeptide chain from given mRNA sequence:

mRNA sequence is: 5'-GCAGGUGCAGGU-3'

The correspoding polypeptide (translation product, based on triplet codons) is

N - Alanine-Glycine-Alanine-Glycine - C

Case A)

DNA sequence: TCT ATA TGC ATG GTC CAG CTC

RNA sequence: AGA UAU ACG UAC CAG GUC GAG

Amino acid sequence: N- Arginine-Tyrosine-Threonine-Tyrosine-Glutamine-Valine-Glutamic acid - C

How is the amino acid sequence of normal protein different from that of the diseased protein

Condition:

Consequences:

Case 2)

DNA sequence: GAC TGA GGA CAC CTC TTC AGA

RNA sequence: CUG ACU CCU GUG GAG AAG UCU

Amino acid sequence: N - Leucine-Threonine-Proline-Valine- Glutamic acid - Lysine -Serine

How is the amino acid sequence of the normal protein different from that of the diseased protein?

This mutation is present in Sickle Cell disease. Normal protein contains Glutamic acid (at fourth position in given amino acid sequence) and Diseased protein contains Valine in place of Glutamic acid.

Condition: Sickle cell disease

Consequence: blood disorder, abnormal hemoglobin shape

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