1. Chromium metal reacts with oxygen to give chromium(III) oxide, Cr2O3. Write a
ID: 1006591 • Letter: 1
Question
1.
Chromium metal reacts with oxygen to give chromium(III) oxide, Cr2O3. Write a balanced equation for the reaction. What mass (in grams) of Cr2O3 is produced if 0.190 g of chromium metal is converted completely to the oxide? What mass of O2 (in grams) is required for the reaction?
_____g Cr2O3
_____g O2
2.
The reaction of methane and water is one way to prepare hydrogen for use as a fuel:
CH4(g) + H2O(g) CO(g) + 3 H2(g)
What is the maximum mass of H2 that can be prepared if the mass of CH4 is 1230 g, the mass of water is 1130 g, and H2O is the limiting reactant?
______ g H2
Explanation / Answer
1) Balanced Reaction
2Cr(s) + 3O2(g) -------- Cr2O3s)
2 moles of Cr will give 1 mole of Cr2O3
Moles of Chromium = 0.190/52 = 0.0036538 moles
Moles of Cr2O3 formed = 0.0036538/2 = 0.0018269 moles
Molar mass of Cr2O3 = 2 * 52 + 48 = 152 gm/mol
Mass of Cr2O3 formed = 0.0018269 moles * 152 gm/mol = 0.2776 grams
2)
CH4(g) + H2O(g) ----- CO(g) + 3H2(g)
Number of moles of water = 1130/18 = 62.777 moles
Since water is the limiting reagent
1 mole of H2O gives 3 moles of H2
Moles of H2 formed = 3 * 62.77778 = 188.333 moles
Mass of H2 formed = 188.333 mol * 2 gm/mol = 376.66 grams
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