1. Many reactions we have been studying are reversible all the way through. Why
ID: 1003998 • Letter: 1
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1. Many reactions we have been studying are reversible all the way through. Why is it important to know whether or not a reaction is reversible or not? (Think practically in a lab setting.)
2. The following compound (C7H14O2, spectrum below) was hydrolyzed with aqueous acid. Draw a mechanism for the hydrolysis. Is the acid catalytic or do you need a stoichiometric amount? Explain in only a few words.
Hand in only page 2. June 10 HW CHEM 241 8 points 1. Many reactions we have been studying are reversible all the way through. Why is it important to know whether or not a reaction is reversible or not? (Think practically in a lab setting.) 2. The following compound (C,H1402, spectrum below) was hydrolyzed with aqueous acid Draw a mechanism for the hydrolysis. Is the acid catalytic or do you need a stoichiometric amount? Explain in only a few words. 6H 3H 2H 2H 2H PPM 3. You want to prepare methyl 2-methylbutanoate from the following starting material (C$H,2O). Show the synthetic steps necessary for the transformation. 3H 3H 3H 2H diastereotopic 1H PPMExplanation / Answer
1. A chemical equation of the form A B represents the transformation of A into B, but it does not imply that all of the reactants will be converted into products, or that the reverse reaction B A cannot occur.In general,both processes (forward and reverse) can be expected to occur, resulting in an equilibrium mixture containing finite amounts of allof the components of the reaction system. If the equilibrium state is one in which significant quantities of both reactants and products are present then the reaction is said reversible.A reaction is said to be complete when the equilibrium composition contains no significant amount of the reactants. However, a reaction that is complete when written in one direction is said "not to occur" when written in the reverse direction.In principle, all chemical reactions are reversible, but this reversibility may not be observable if the fraction of products in the equilibrium mixture is very small, or if the reverse reaction is very slow
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