The bonding in iron (III) nitrite is Ionic only Covalent only Metallic and coval
ID: 1001271 • Letter: T
Question
The bonding in iron (III) nitrite is Ionic only Covalent only Metallic and covalent Ionic and metallic Ionic and covalent For questions 13-15, consider the chemical reaction that occurs when 50 g of dinitrogen tetroxide (N_2O_4, 92.02 g/mol) reacts with 47.5 g of hydrazine (N_2H_4, 32.06 g/mol) to produce nitrogen gas and water. N_2O_4(l) + 2N_2H_4(l) rightarrow 3N_2 (g) + 4H_2 O(l) If the reaction produces 30 g of nitrogen gas, what is the percent yield of this reaction? 16.9% 65.7% 31.3% 48.2% How many moles of excess reagent are left over after the reaction has run to completion if the percent yield of the reaction was 100%? 0.94 1.09 0.39 1.48 If the reaction is run at STI* and the yield is 54%, what is the maximum volume of N_2 formed (in liters)? 36.5 liters 19.7 liters 21.5 liters 39.8 liters The density of gold is 19.3 grams/cm^3. Which equation below represents the of this density to units of nanograms/m^3? Density (ng/m^3) = 19.3 Times 10^-9 Times 10^6 Density (ng/m^3) = 19.3 Times 10^-9 Times 10^2 Density (ng/m^3) = 19.3 Times 10^9 Times 10^2 Density (ng/m^3) = 19.3 Times 10^-9 Times 10^6 Consider the molecular orbital diagram of O_2 with a bond order of 2. How many must be added to the O_2 molecule to reduce the bond order to zero. 4 electrons 3 electrons 2 electrons 1 electronExplanation / Answer
12) The bonding in Fe(III)nitrate is,
a. Ionic only
13) For the reaction, the percent yield would be,
b. 65.7%
14) Excess moles left of N2H4 is,
c. 0.39
15) At STP volume of N2 formed is,
b. 19.7 L
16) Density conversion factor is,
d. density (ng/m^3) = 19.3 x 10^9 x 10^6
17) Number of electrons to be added to reduce bond order to zero of O2 is,
a. 4 electrons
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