Analysis of a hydrate of iron (iii) chloride revealed that in a 10.00 g sample o

Question

Analysis of a hydrate of iron (iii) chloride revealed that in a 10.00 g sample of a hydrate, 6.00 g is anhydrous iron(iii) chloride and 4.00 g is water. Determine the formula and name of a hydrate. Analysis of a hydrate of iron (iii) chloride revealed that in a 10.00 g sample of a hydrate, 6.00 g is anhydrous iron(iii) chloride and 4.00 g is water. Determine the formula and name of a hydrate. Analysis of a hydrate of iron (iii) chloride revealed that in a 10.00 g sample of a hydrate, 6.00 g is anhydrous iron(iii) chloride and 4.00 g is water. Determine the formula and name of a hydrate.

Explanation / Answer

FeCl3 .XH2O = consider the formula of hydrate

mass of hydrate = 10g

mass of anhydrous FeCl3 = 6g

mass of water in hydrate = 10g - 6g = 4 grams of water

- convert the mass of anhydrate to moles: 6g / 162.204 g/mol = 0.0369 mol

- convert the mass of water to moles: 4g / 18g/mol = 0.222 mol

find the mole H2O to mole Fecl3 ratio: 0.222/0.0369 = 6

6moles of H20 is present with one mole anhydrous Fecl3 in hydrate form

so formula of hydrate : FeCl3 .6H2O

Iron (III) Chloride Hexahydrate

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