On a sheet of paper, write the answer to each question. Use this balanced equati
ID: 999448 • Letter: O
Question
On a sheet of paper, write the answer to each question. Use this balanced equation: 2AI(OH)_3 + 3H_2SO_4 rightarrow AI_2(SO_4)_3 + 6H_2O You need to convert the mass of Al_2(SO_4)_3 to the mass of water. How many conversion factors will you need? You need to convert the mass of Al(OH)_3 to moles of water How many conversion factors will you need? To convert from grams of H_2SO_4 to moles of H_2SO_4, what conversion factor would you use? If 216 g of water forms, how many moles of AI_2(SO_4)_3 form? If 736 g of H_2SO_4 reacts with excess Al(OH)_3 how many moles of Al_2 (SO_4)_3 form? You have 132 g of Al(OH)_3. This reacts with excess H_2SO_4. How many grams of water are produced? On a sheet of paper, write the answer to each question. A chemist burs 175 g of solid magnesium in excess O_2 gas. All of the metal reacts. He wants to know how many grams of the oxygen reacted. Write a conversion map for this problem.(This is a combination reaction. Write a balanced equation first.) Solve the problem in question 7. What mass of oxygen reacted? A chemist has a small amount of diatomic bromine. She uses all of it in a single-replacement reaction with excess K1.28.2 g of KBr is produced. She wants to know the mass of the bromine. Write a conversion map for this problem. Solve the problem in question 9. How many grams of bromine did the chemist have?Explanation / Answer
1) two conversion factors
2) one conversion factor
3) moles = mass / molar mass
4)
2Al (OH)3 + 3 H2SO4 ------------------>Al2(SO4)3 + 3H2O
156g 294g 342g 54g
342 g Al2(SO4)2 ----------------->54 g H2O
x g Al2(SO4)2 ----------------->216 g H2O
x = 1368 g Al2(SO4)2
moles of Al2(SO4)2 = 1368 / 342
= 4
moles of Al2(SO4)2 = 4
5)
2Al (OH)3 + 3 H2SO4 ------------------>Al2(SO4)3 + 3H2O
156g 294g 342g 54g
736g
Al2(SO4)3 mass = 342 x 736 / 294
= 856 .16 g
moles of Al2(SO4)3 = 856 .16 / 342
= 2.5
moles of Al2(SO4)3 = 2.5
6)
2Al (OH)3 + 3 H2SO4 ------------------>Al2(SO4)3 + 3H2O
156g 54g
132g 45.69
mass of H2O produced = 54 x 132 / 156
= 45.69
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