HEM 212 Midterm 2 Version 8 W2016 Page 2 2. In which direction will the equilibr
ID: 999405 • Letter: H
Question
HEM 212 Midterm 2 Version 8 W2016 Page 2 2. In which direction will the equilibrium shift when more Ha is added to this equilibrium reaction? CO(g) + 2 H2(g) F-CH3OH(g) A. Shift toward reactants because adding H2 has caused a decrease in the value of Q B. Shift toward product because adding H2 has caused a decrease in the value of Q C. Shift toward product because adding Hz has caused an increase in the value of Q D. Shift toward reactants because adding Ha has caused an increase in the value of Q E. The equilibrium will not shift. What is the pH of a 0.0023 M hydrochloric acid solution? A. 7.00 B. 6.07 C. 11.36 D. 2.64 E. 7.93 3. 4. Identify the correctly matched conjugate acid-base pair from this reaction. A. HPO is an acid and OH is its conjugate base. B. H O is an acid and HP0 is its conjugate base. C. H2O is an acid and OH is its conjugate base. D. HPO is an acid and H:0 is its conjugate base. E. HPO is an acid and H:POs is its conjugate base. 5. Classify sulfurous acid, H2SOs, shown here in a neutralization reaction with hydroxide H2so,(aq) + 2 OH-(ag) SO32-(agi + 2 H300 A. H SOs is neither an Arrhenius acid nor a Bronsted-Lowry acid B. HSO, is a Lewis base. C. H2SO, is both an Arrhenius acid and a Bronsted-Lowry acid. D. H2SO, is an Arrhenius base and a Brensted-Lowry base. E. H2SOs is an Arrhenius acid, but not a Brensted-Lowry acid. 6. If a solution has a pH value of 3.68, what is the pOH value? A. 10.32 B. 2.09 C. 7.00 D. 3.80 E. 3.68Explanation / Answer
2) B
3) pH = -log 0.0023 = 2.64 D
4) A
5) C
6) pH + pOH = 14 pOH = 14 -pH = 14 - 3.68 = 10.32 A
7) pH = 3.7 the pOH = 14 - 3.7 = 10.3 OH = 5x10-11 C
8) A
9) A
10) NH42/NH3 = kb 0.51M x 1.8x10-5 = NH42 = 9.72x10-6 M NH4 = 3.1x10-3 D
11) D
12) B
13) A
14) Kb = 1/Ka = 1.6x104 A
15) (A-2)2 = (H2AKa)1/2xKa2 = 1.12x10-6 D
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