FeCl_3 can be prepared from iron and chlorine in two ways: Which is true of the
ID: 999167 • Letter: F
Question
FeCl_3 can be prepared from iron and chlorine in two ways: Which is true of the enthalpy changes of these routes? The single-step route has an enthalpy changes that can be larger or smaller than the two-step route. depending upon conditions. The single-step route will have a smaller enthalpy changes than the two-step route. The single-step route will have a larger enthalpy change than the two-step route. The overall enthalpy changes for the two routes are the same Use these data to determine the enthalpy change for the reaction. Na_2O_2 rightarrow Na_2O+ 1/2 O_2 +99 KJ -99KJ +198 KJ cannot determine without delta H_f for O_2 Chlorine will oxidize I^- as shown in this equation: Cl_2 + 2l^- rightarrow l_2 + 2Cl^- Use reactivity trends to predict which can be used to prepare Br_2 from Br^-. F + Br^- Cl_2 + Br^- l_2 + Br^- III only I and II only II and III only I, II, and III A buried metal tank will not corrode if it is wired to a metal rod that corrodes more easily, Which combination protects the tank from corrosion? Mg rod and S_n tank Fe rod and Z_n tank Fe rod and Al tank Cu rod and Zn tank Given these standard reduction species will reduce Co^2+ under Pb,Cu Pb^2-,Cu^2+ Which part in this electrochemical cell is the anode? 1 2 4 Predict the voltage for the cell Cd | Cd^2(1 M) || Ni^2 (1 M) Cd^2+(aq) + 2e^- rightarrow Cd E'' = - 0.402 Ni^2+(aq) + 2e^- rightarrow Ni E'' = -0.236 -0.638 v What happen during this reaction? Cd + NiO_2 rightarrow Cd(OH)_2 + Ni(OH) Cadmium metal is oxidized. Cadmium metal is reduced The O atom in H_2O is reduced. The Ni atom is NiO_2 oxidized. The solubility of a salt is water usually increase increasing temperature because the process is exothermic so dissolution occurs faster. exothermic so dissolution occurs faster. exothermic to the higher temperature favors dissolution. exothermic to the higher temperatures favor dissolution. Which reagent, when added to BaCl_2(aq) and filtered, can produce a solution that is essentially HCl(aq)?Explanation / Answer
16) Ho = Hof of products - Hof of reactants
= -416 - [ -515 + 0]
= + 99 kJ
17) B - I,II only
F, Cl are more reactive than Br.
I is less reactive than Br.
21) Cd anode , Ni cathode
Eo = cathode reduction potential - anode reduction potential
= -0.236 - (-0.402)
= + 0.166 V
Hence, ans = c
22) Oxidation number of Cd is increased from 0 to +2.
Therefore,Cadmium metal is oxidized.
Hence,
ans = a
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