Assume a certain adult requires 236 mL of pure oxygen per minute. Assume inhaled

Question

Assume a certain adult requires 236 mL of pure oxygen per minute. Assume inhaled air contains 20.0 percent oxygen by volume and exhaled air is 16.0 percent. (Also, assume that the volume of inhaled air is equal to that of the exhaled air.) Calculate the total volume (in liters) of pure oxygen gas (O_2) the adult breathes in a day. Enter your answer in scientific notation. In a city with heavy traffic, assume the air contains 1.92 times 10^-6 L of carbon monoxide (a poisonous gas) per liter. Calculate the daily intake of carbon monoxide in liters by the person.

Explanation / Answer

Inhaled air = 20%

Exhaled air = 16%

Adults breathing air = 20-16 = 4% per minute

Adults required air =236 mL per minute (According to the question)

= 236 x 4 / 100

= 9.44 mL / min

1 day = 24 h

1 h = 60 min

per day

= 24 x 60 min

= 1440 min

1 minute --------------- 9.44 mL

1440 min -------------- ?

= 1440 x 9.44

= 13593.6 mL

= 13.593 x 103 mL

1 litre = 103 mL

= 13.593 L

= 0.1359 x 102 L

Part-2:

CO volume in air = 1.92 x10-6 L per litre of air

Daily intake CO = ?

1 L -------------------- 1.92 x 10-6

13.593 L ---------- ?

= 13.593 x 1.92 x 10-6

= 26.098 x 10-6 L

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