1. Determine the number of moles of copper(Il) nitrate in 25.06 mL of a 2.44 M C
ID: 996410 • Letter: 1
Question
Explanation / Answer
Ans 1: you are right that 0.0611 moles of copper nitrate is present in 2.44M of 25.6 ml solution.
Ans2: molecular weight of potassium permagnate is158.034. if you do the same calculation like for above qns. you will get 0.237 gm as a solution. (C) is the correct answer.
M=W/M X1000/V
Ans 3: C6H12O6 is non electrolyte because electrolytes are those compounds which dissociate in water and forms cation and abion. Here glucose doesnot dissociate in cation and anion.
Ans 4: Ammonium chloride (NH4Cl) is a strong electrolyte it dissociate in water as a NH4+ and Cl- ions. So the concentration of NH4+ which is ammonium is equal to conc. of chloride ion. So the answer is 0.22M.
Ans 5: SrO + 2HNO3--> Sr(NO3)2 +H2O
1.034 moles of nitric acid is reqired for complete reaction.So here 2HNO3=1.034. so 1.034/2=0.517 moles is required for SrO.
The molecular weight of SrO =103.6
If you multiply 103.6 X0.517 = 53.57.
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