The porphine molecule(Figure 2) is a tetradentate ligand and is the basis for ma

Q: The porphine molecule(Figure 2) is a tetradentate ligand and is the basis for ma

dGo = dHo -TdSo where dHo = -28.5 KJ = -28500 J = -( 28500) - ( 298) ( 6.32) = -30383.36 J we have relation dGo = -RT ln Kf -30383.36 = -8.314 x 298 ln K Kf = 2.12 x10^ 5

ID: 996281 • Letter: T

Question

The porphine molecule(Figure 2) is a tetradentate ligand and is the basis for many porphyrins found in biological systems. Porphyrins are complexes with metal ions and have different substituents attached to the carbons of the porphine ligand. Heme (which contains Fe2+ ) and chlorophyll (which contains Mg2+ ) are two common examples.

Part B

Consider the reaction of a generic metal ion (Mn+ ) with a generic porphine molecule (por ):

M(H2O)mn+(aq)+por(aq)M(por)n+(aq)+mH2O(l)

Based on the values of standard enthalpy, H , and entropy, S , shown here,

what is the value of the formation constant, Kf , for the reaction at 25 C ?

H S -28.5 kJ 6.32 J/K

Explanation / Answer

dGo = dHo -TdSo where dHo = -28.5 KJ = -28500 J

= -( 28500) - ( 298) ( 6.32)

= -30383.36 J

we have relation dGo = -RT ln Kf

-30383.36 = -8.314 x 298 ln K

Kf = 2.12 x10^ 5

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The porphine molecule(Figure 2) is a tetradentate ligand and is the basis for ma

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