How many signals would you expect to see in the 1H NMR spectrum of the following
ID: 995280 • Letter: H
Question
How many signals would you expect to see in the 1H NMR spectrum of the following compound? CH_3CH_2CH_2CH_3 3 2 1 6 4 How many signals would you expect to see in the 1 H NMT spectrum of the following compound? 5 2 4 6 3 What splitting pattern is observed in the proton NMR spectrum for the indicated hydrogens? triplet quartet doublet singlet Which of the following is an aromatic hydrocarbon? Which of the structure below would be aromatic? Which of the following is the efectrophile that attacks the aromatic ring during nitrationh?Explanation / Answer
6. Butane
Two different types of protrons. One CH3 (4 methyl protrons) and second CH2 (methylene protrons). So 2 signals
Answer is (B)
7. p-xylene
Two different types of protrons. One (4 Protrons) of aromatic ring and second CH3 (methyl protrons). So 2 signals.
Answer is (B).
8. 1-ethoxy-4-methylbenzene
CH2 - near by CH3. Three protrons, so its a quartet.
Answer is (B).
9. Answer is (c) - III.
Structure III is Toluene. And Toluene is aromatic compound. Its a hydrocarbon.
Structure I is Furane which is an aromatic compound. But it contains oxygen and hence not hydrocarbon.
10. Answer is (D) - III & IV.
Cyclopropene has the correct number of pi electrons to be aromatic, 4(0) + 2 =2, but it does not have a continuous cycle of 2p orbitals. If the CH2 group were to become an sp2-hybridized cation with a vacant 2p orbital, then the overlap of orbitals is continuous and the cyclopropenyl cation should be aromatic.
The tropylium ion is an aromatic species with a formula of [C7H7]+. It is a heptagonal, planar, cyclic ion; as well, it has 6 -electrons (4n + 2, where n = 1), which fulfills Hückel's rule of aromaticity.
11. Answer is (E) - NO2+.
H2SO4 + HNO3 is the nitrating agent, it produces NO2+.
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