1.A solution has [H3O+] = 7.6 x 10 -5 M. Use the ion product constant of water (

ID: 994737 • Letter: 1

Question

1.A solution has [H3O+] = 7.6 x 10 -5 M. Use the ion product constant of water (Kw=[H3O+][OH-]) to find te [OH-] of the solution.

2. A solution has [OH-]=2.1x10-2 M. Use the ion product constant of water to find the [H3O+] of the solution.

3. Classify each solution as acidic, basic or neutral accordong to its pH value.

a)pH= 8.0

b) pH= 7.0

c)pH= 3.5

d)pH=6.1

4. What is the pH of a solution with [H3O+]= 2.8 X 10-5 M?

a)10.48

b)1.00

c)-4.55

d)4.55

5. What is [OH-] in a solution with a pH of 9.55?

a) 2.82x10 4 M

b)4.45 M

c)3.55 x 10 -5 M

d)2.82 x 10 -10 M

1.A solution has [H3O+] = 7.6 x 10 -5 M. Use the ion product constant of water (Kw=[H3O+][OH-]) to find te [OH-] of the solution.

Apply

Kw = 10^-14

then

Kw = Ka*KB

Kb = Kw/Ka= (10^-14)/(7.6*10^-5) =1.3157*10^-10

similarly

10^-14 = (2.1*10^-2)[H+]

[H+] = (10^-14 )/(2.1*10^-2)

[H+ = 4.761*10^-13

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