1. If the lone pair were not present on the nitrogen in NBr 3 of the 3-D structu
ID: 994485 • Letter: 1
Question
1. If the lone pair were not present on the nitrogen in NBr3 of the 3-D structures, what would be the shape of the species?
2. What would happen to the polarity if the lone pair were not present on the nitrogen in the NBr3 molecule?
3. Mg(s) + 2HCl(aq) MgCl2(aq) + H2(g)
The reaction above is an oxidation-reduction reaction. What is being oxidized and what is being reduced? Explain your answer.
4. In order for this reaction to work properly to give the correct molar volume of an ideal gas, which must be the limiting reactant in the reaction? Explain your answer.
5. If there is an unreacted metal remaining at the end of the reaction, what would that do to your calculated molar volume? Be specific. Do not merely say that “it would be
6. If you had used 0.030 g of magnesium in a first trial and 0.040 g in the second, would you expect the molar volume at STP to be larger or smaller in the second trial? Explain your answer. Do not merely explain by saying molar volume is an intensive property. Explain WHY its molar volume is not dependent on the sample size.
7. Hydrogen is a real gas. a) Under what conditions do you expect it to deviate from ideal gas behavior? Explain. b) Is it reasonable to consider hydrogen as an ideal gas under the conditions of this experiment? Explain.
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Explanation / Answer
1. If the lone pair were not present on the nitrogen in NBr3 then its shape would be trigonal planar .
2 .Shape will be trigonal planar so there is no polarity in the molecule ,If the lone pair were not present on the nitrogen in NBr3.
3. Mg is being oxidised and Cl is being reduced.if solid Mg react with HCl .Mg will lose 2 e- so that oxidation state of Mg will becomes 2 this is oxidation and Cl will takes 1 e- and becomes Cl- so reduction.Removal of e- called oxidation and addtion of e- called reduction.
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