1. If you have two identically-sized solid blocks completely immersed in water a
ID: 994444 • Letter: 1
Question
1. If you have two identically-sized solid blocks completely immersed in water and one is ironwood (density = 1.17 g/cm3) and one is lead (density = 11.34g/cm3), what is the difference in the buoyant forces acting on the two blocks?
2. If you have a 10.0 cm3 block of ironwood (density = 1.17 g/cm3) and it is completely immersed in water, what is the buoyant force acting on the block?
2a. What is the force of grabity acting on the 10.0cm3 block of ironwood?
2b. What is the net force acting upward or downward on the block of ironwood?
Explanation / Answer
This is physycs actually, but I'm gonna answer it here instead of skipping.
1. The buoyant force is calculated as:
Fb = m*g
and m = d*V
We don't have here neither the mass or volume of these blocks, but still we can find a difference:
Fb1 = m1 * g
Fb1 = d1*V * g
Fb1 = 1.17*9.8*V
Fb1 = 11.47V
Fb2 = m2*g
Fb2 = d2*V*g
Fb2 = 11.34 * 9.8 * V
Fb2 = 111.32V
As both blocks have the same size, we can assume that they both have the same volume so the difference:
Fb2 - Fb1 = 111.32V - 11.47V
Fb2-Fb1 = 99.85V or we can approximate this to 100V
2. Fb = (10*1.17)*9.8
Fb = 114.66 N
The force of gravity acting here would be only the weight, which is 114.66 N but with a contrary sense (-114.66 N)
Finally the net force would be: Fb1 + W
But as these are the only forces acting and in opposite directions, we can say that the net force = 0.
Hope this helps
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.