I need help with just the setup on these questions, powerpoint shows the answer,

Question

I need help with just the setup on these questions, powerpoint shows the answer, however i would like to know how to calculate these questions TIA.. A sample of water at 10.0 ° C absorbs 4410 J of heat energy. The temperature of the sample increases to 72.0 °C. What is the mass of the water? The specific heat of liquid water is 4.184 J/g°C.

and,

A sample of liquid water at 100. °C absorbs 113 kJ of heat energy. How much of the water will be converted to steam? The heat of vaporization of water is 2259 J/g.  

Explanation / Answer

Q = m*C*dT
m = Mass

C = specific heat of liquid water is 4.184 J/g°C.

dt = temperature difference

4410 = m x 4.184 x 72-10

m = 17

Mass of the water is 17 gm.

question 2

113 x 103 = m x 2259

m = 50.02 gm

50.02 gm of the water will be converted to steam

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