Ten test tube mystery We will be given ten unlabeled test tubes. Using the test
ID: 991068 • Letter: T
Question
Ten test tube mystery
We will be given ten unlabeled test tubes. Using the test tube contents and absolutely nothing else, we must identify the contents of each testtube. Each test tube will contain one of the following:
Ni(NO3)2
Al(NO3)3
SnCl4 in HCl
Cu(NO3)2
AgNO3
Ca(NO3)2
NH3
NaOH
H2SO4
HCl
We must create a reaction matrix. I have created one but would like it to be corrected or emphasized.
ppt= precipitate
NR= no reaction
D= precipiates dissolves in excess
Ni(NO3)2
Al(NO3)3
SnCl4 in HCl
Cu(NO3)2
AgNO3
Ca(NO3)2
NH3
NaOH
H2SO4
HCl
Ni(NO3)2
NR
Al(NO3)3
SnCl4 in HCl
Cu(NO3)2
AgNO3
Ca(NO3)2
NH3
NaOH
HCl
Ni(NO3)2
Al(NO3)3
SnCl4 in HCl
Cu(NO3)2
AgNO3
Ca(NO3)2
NH3
NaOH
H2SO4
HCl
Ni(NO3)2
NR NR NR NRNR
NR D, BLUE SOLUTION PPT NR NRAl(NO3)3
NR NR NR NR NR PPT PPT, D NR NRSnCl4 in HCl
NR GREEN SOLUTION PPT NR PPT, HEAT PPT, D, HEAT NR NRCu(NO3)2
NR NR NR PPT, D PPT NR GREEN SOLUTIONAgNO3
NR NR BROWN PPT, D BROWN PPT PPT PPTCa(NO3)2
NR PPT PPT NR NRNH3
NR HEAT HEAT HEATNaOH
NR HEAT PPT, HEAT H2SO4 NR NRHCl
NRExplanation / Answer
Corrections/additions to the table content
Al(NO3)2
Al(NO3)3 with NaOH forms ppt of Al(OH)3 which Dissolved in excess OH- to form Al(OH)4-.
Al(OH)3 with NH3 forms ppt of Al(OH)3
Cu(NO3)2
Reacts with NH3 to form [Cu(NH)3]2+ deep blue solution
Reacts with aq.H2SO4 to form CuSO4 which is blue in color
AgNO3
Reacts with SnCl4 to form ppt of AgCl
Ca(NO3)2
Reacts with H2SO4 to form ppt of CaSO4
Reacts with HCl to form ppt of CaCl2
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