As a chemist for an agricultural products company, you have just developed a new
ID: 989767 • Letter: A
Question
As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the potential to kill weeds effectively. A sparingly soluble salt, Herbigon is dissolved in 1 Macetic acid for technical reasons having to do with its production. You have determined that the solubility product Ksp of Herbigon is 8.90×106.
Although the formula of this new chemical is a trade secret, it can be revealed that the formula for Herbigon is X-acetate (XCH3COO, where "X" represents the top-secret cation of the salt). It is this cation that kills weeds. Since it is critical to have Herbigon dissolved (it won't kill weeds as a suspension), you are working on adjusting the pH so Herbigon will be soluble at the concentration needed to kill weeds. What pH must the solution have to yield a solution in which the concentration of X+ is 3.00×103M ? The pKa of acetic acid is 4.76.
Express your answer numerically.
pH =Explanation / Answer
this is a salt
A- is formed
the next equilibrium is formed, the conjugate acid and water
A- + H2O <-> HA + OH-
Kb by definition since it is an base:
Kb = [HA ][OH-]/[A-]
Ka can be calcualted as follows:
Kb = Kw/Ka = (10^-14)/(1.8*10^-5) = 5.55*10^-10
and;
assume x = [OH-]
[OH-] = x= [HA] due to equilibrium
[A-] = M-x = 0.42-x
Kb = [HA ][OH-]/[A-]
5.55*10^-10 = x*x/(3*10^-3-x)
solve for x with quadratic equation
x = OH- =1.29*10^-6
[OH-] = 1.29*10^-6 M
pOH = -log(OH-) = -log(1.29*10^-6) = 5.89
pH = 14-5.89= 8.11
pH = 8.11
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