CHEM HELP PLEASE!!! The half-life of a reaction, t 1/2 , is the time it takes fo

Question

CHEM HELP PLEASE!!! The half-life of a reaction, t1/2 , is the time it takes for the reactant concentration [A] to decrease by half. For example, after one half-life the concentration falls from the initial concentration [A]0 to [A]0/2 , after a second half-life to [A]0/4 , after a third half-life to [A]0/8 , and so on. on.

Part B

A certain second-order reaction (Bproducts ) has a rate constant of 1.55×103M1s1 at 27 C and an initial half-life of 206 s . What is the concentration of the reactant B after one half-life?

Explanation / Answer

for second order reaction,

t1/2 = 1 / k * [A0]

[A0] = t1/2 * k

[A0] = 206 * 1.55 *10^-3

[A0] = 0.3193 M

and also we know the formula

(t1/2)1 / (t1/2)2 = a2 / a1

206 / 2 * 206 = a2 / 0.3193

a2 = 0.1663 M

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