1. Isopropyl alcohol is mixed with water to produce a 35.0% (v/v) alcohol soluti

Question

1. Isopropyl alcohol is mixed with water to produce a 35.0% (v/v) alcohol solution. How many milliliters of each component are present in 745 mL of this solution? (Assume that volumes are additive.)

1A- _____ mL alcohol

1B-_____ mL water

2. Calculate the volume percent of solute in the following solutions.

2A- 16.9 mL of methyl alcohol in enough water to give 547 mL of solution. _____%

2B- 68.1 mL of ethylene glycol in enough water to give 229 mL of solution _____ %

3. How many grams of chlorine gas are needed to make 3.30 * 10^6 g of a solution that is 1.30 ppm chlorine by mass?

3A- _____ g Cl2

4. Calculate the molarity of the following solutions

4A- 0.550 mol of Na2S in 1.20 L of solution _____ M

4B- 32.3 g of MgS in 743 ml of solution _____ M

5. Calculate the molarity of the following solutions

5A- 0.300 mol of NaOH in 2.75 L of solution _____ M

5B- 20.5 g of NaCi in 849 mL of solution _____ M

6. How many moles of NaOH are present in 17.0 mL of 0.240 M NaOH?

6A- _____ mol

7. If 5.97g of CuNO3 is dissolved in water to make a 0.870 M solution what is the volume of the solution?

7A- _____ mL

8. How many grams of solute are present in 625 mL of 0.830 M KBr?

8A- _____ g

9- Assuming equal concenrations and complete dissociation rank these aqueous solutions by their freezing points. Starting with highest to lowest freezing points. NaNO3 CoBr3 K2CO3

9A-

Explanation / Answer

1) Given that 35% of the solution is water so you just multiply the whole solution (865mL) by 35% (0.35) to get the amount of alcohol and you know that there is 65%

0.35 x 865mL = 302.75mL of Isopropyl alcohol
0.65 x 865mL = 562.25mL of water.

4)

A) 0.550 moles Na2S/1.20 L= 0.45 M

B) 1 mole of MgS = 24.3 + 32.1 = 56.4 g

32.3 g MgS x 1 mol / 56.4 g = 0.5726 mol

M = 0.5726 mol / 0.743 L = 0.770 mol/L

5)

A) (0.300 mol) / (2.75 L) = 0.109 mol/L

B) ((20.5 g NaCl) / (58.4430 g NaCl/mol)) / (0.849 L) = 0.413 mol/L

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