The following information is given antimony at 1 atm. Boiling point - 1.44*10^3
ID: 984380 • Letter: T
Question
The following information is given antimony at 1 atm. Boiling point - 1.44*10^3 degree C Delta H_vap (1.440*10^3 degree C)- 1.605 * 10^3 j/g melting point -631.0 degree C Delta H_fus(631.0 degree C) - 161.1 j/g specific heat solid -0.2090 j/g degree C specific heat liquid - 0.2590 j/g degree C A 28.80 g sample of liquid antimony at 746.0 degree C is poured into a mold and allowed to cool to 25.0 degree C.How many kj of energy are released in this process.Report in the answer as a positive number. kjExplanation / Answer
The "liquid Antimony" in this case is going to do three things:
a) as a liquid, cooles to 7460C to 6310C
b) At 6310C 28.8 g will freeze
c) as a solid, the temperature reduces to 250 C
Q = m c T
Q = quantity of heat in joules (J)
m = mass of the substance acting as the environment in
grams (g)
c = specific heat capacity in J/(g oC)
T = change in temperature = Tfinal - Tinitial in oC
cooles to 7460C to 6310C + To freeze solid + temperature reduces to 250 C
Here are the numbers:
= 28.8 x (746-631) x 0.259 + 28.8 x 161.1 /121.76 + 28.8 x (631-25) x 0.209
= 857.81 + 38.105 + 3647.63
= 4543.55 J or 4.543 Kj heat will be relesed
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