1. For the half-reaction: Cu 2+ + 2e - --> Cu, the standard reduction potential
ID: 984234 • Letter: 1
Question
1. For the half-reaction: Cu2+ + 2e- --> Cu, the standard reduction potential (E°) is +0.3V. For the half-reaction: Fe2+ + 2e- --> Fe, the value of E° is -0.4V. Based on the above reduction potentials, what is the reduction potential for the following reaction (Fe2+ + Cu --> Fe + Cu2+)?
a. +1.4 V b. -0.7 V c. none
2. Consider reaction 1, which is A + B <--> C + D; reaction 2, which is C + D <--> E + F; and reaction 3, which is E + F <--> G + H. If the equilibrium constant for the first reaction is x, the equilibrium constant for the second reaction is y, and the equilibrium constant for the third reaction is z, then, in terms of these equilibrium constants, what would be the equilibrium constant for the following net reaction (A + B <--> G + H)?
a. xyz b. x/yz c. none
Explanation / Answer
Fe2+ + Cu --> Fe + Cu2+
Cu2+ + 2e- --> Cu = 0.3
Fe2+ + 2e- --> Fe E -0.4
then
invert(1)
Ecell = -0.4 - 0.3 = -0.7 V
2)
answer is none
the actual value will be
[G][H]/[A]B]
which is none of above
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