tivity do CHEM 110 Spring 2016 Sect. O cengageBrain . My Horne (,\' Owix2 Iine t
ID: 983853 • Letter: T
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tivity do CHEM 110 Spring 2016 Sect. O cengageBrain . My Horne (,' Owix2 Iine teaching-x Use the Referesces to access important valees if needed for thi qaestion. For the following reaction, 3.14 grams of exygen gas are mixed with excess butane (C,Hia) The reaction yields 1.77 grams of carbon diexide butane (C H) g+ esygrn () carboa dioxide ()+water (a) What is the theoretical yield of carbon dieside ? What is the percent yield of carbon dioxide grams Slbenit Answer Retry Entire Group 3 more group attempts remainingExplanation / Answer
Part A.
balanced equation : 2C4H10 + 13O2 ---> 8CO2 + 10H2O
moles of O2 = 3.14 g/32 g/mol = 0.098 mols
13 moles of O2 gives 8 moles of CO2
So moles of CO2 produced by 0.098 mol O2 = 0.098 x 8/13 = 0.06 mols
theoretical yield of CO2 = 0.06 mol x 44.01 g/mol = 2.66 g
Percent yield of CO2 = (1.77/2.66) x 100 = 66.54%
Part B.
balanced equation : SiF4 + 4H2O ---> 4HF + SiO2
moles of SiF4 = 3.09 g/104.08 g/mol = 0.03 mols
1 mole of SiF4 produces 4 moles of HF
So moles of HF produced by 0.03 mols of SiF4 = 0.12 mols
Theoretical yield of HF = 0.12 mol x 20.01 g/mol = 2.38 g
Percent yield of HF = (2.16/2.38) x 100 = 90.76%
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