Please show all work and thoroughly explain! For the reaction 2A + B --> product

Question

Please show all work and thoroughly explain!

For the reaction

                2A + B --> products, determine the rate law for the reaction given the following data:

Initial Concentration, M            Initial Rates, M . s - 1

A

B

0.10

0.10

2.0 x 10-2

0.20

0.10

8.0 x 10-2

0.30

0.10

1.8 x 10-1

0.20

0.20

8.0 x 10-2

0.30

0.30

1.8 x 10-1

Initial Concentration, M            Initial Rates, M . s - 1

A

B

Initial Rates M.s^-1

0.10

0.10

2.0 x 10-2

0.20

0.10

8.0 x 10-2

0.30

0.10

1.8 x 10-1

0.20

0.20

8.0 x 10-2

0.30

0.30

1.8 x 10-1

Explanation / Answer

(R1/R2) = (A1/A2)^n

order w.r.t A

((2.0*10^(-2))/(8.0*10^(-2))) = (0.1/0.2)^n

n = 2

order w.r.t B

((8.0*10^(-2))/(8.0*10^(-2))) = (0.1/0.2)^m

m = 0

rate law

Rate = K[A]^2[B]^0

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