Question 14 of 32 Mapd sapling learning Assume that the complete combustion of o

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Question 14 of 32 Mapd sapling learning Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol (AG-2870 kJ/mol). If one contraction cycle in muscle requires 53 kJ, and the energy from the combustion of glucose is converted with an efficiency of 35% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number Number cycles per mole glucose xit Previous Gvo Up & Viow Sciution O Check Answer O Next

Explanation / Answer

Answer:-The total combustion of 1 mole of Glucose to carbon dioxide and water liberates 2870kJ/mole.

1 muscle contraction require 53kJ of energy.

According to question,energy from the combustion of Glucose is converted with an efficiency of 35% to the contraction.

35% of 2870 = (35 /100) x2870 =100.45kJ

If for 1 contraction 53kJ energy is require then 100.45 /53 =1.89 =2

So, 2 contraction cycle is possible after combustion of 1 mole of Glucose.

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