Cylindrical piston with rigid impermeable adiabatic walls. The piston has a cros
ID: 982660 • Letter: C
Question
Cylindrical piston with rigid impermeable adiabatic walls. The piston has a cross sectional area of A - 0.10m2 and the cylinder enclosing the gas has a height of h = 1cm. The gas inside the piston has a temperature T = 300K. Recall that the internal energy for an ideal gas is where c_ym = (3/2) R is the molar heat capacity for the ideal gas. Calculate the pressure and the internal energy of the ideal gas. Suppose that a (very heavy) mass w = 153.10^3 kg is placed on the top of the piston, but that the piston top remains rigid. Determine the external pressure applied on the cylinder by the mass and also the equilibrium volume for the gas. Remember, the cylinder forms a rigid enclosure and that the gravitational constant g - 9.81 m s^-2. Suppose that the piston is now allowed to move within the cylinder, but that the walls remain a diabetic and impermeable so that no heat flows into the gas. The gas system will ultimately move to a new equilibrium state. We will now characterize the final equilibrium state and the changes resulting from the process. Define the(Total System)= (the gas enclosed in the cylinder)plus (the mass placed on the piston) The internal energy, Ur, for the total system then satisfies the following relation: UrU+ Um where U is the energy of the gas and Um is the gravitational potential energy of the mass.Let us assume that this total system forms an isolated system. Determine the change in the internal energy of the Total System, UT. Determine the pressure of the gas at equilibrium. Demonstrate that the final volume of the gas is 1.4 * 10^-3 m^3.Calculate the work done on the gas, w. Calculate the change in gravitational potential energy of the mass. Calculate the change in internal energy of the gasExplanation / Answer
internal energy:
U = nCv,mT
but, Cv,m = 3/2R
U= n3/2RT
U= 1× 3/2 × 0.08206×300 = 36.972
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