the osmotic pressure at 25.0°C is observed to . What is the mass percent of MgCl

Question

the osmotic pressure at 25.0°C is observed to . What is the mass percent of MgCl2 in the solid? (Assume ideal behavior for the solution.) be 0.5950 atm 115. Formic acid (HCO,H) is a monoprotic acid that ionizes only par- tially in aqueous solutions. A 0.10 M formic acid solution is 4.2% ionized. Assuming that the molarity and molality of the solution are the same, calculate the freezing point and the boiling point of 0.10 M formic acid. 116. You have a solution of two volatile liquids, A and B (assume ideal behavior). Pure liquid A has a vapor pressure of 350.0 torr and pure liquid B has a vapor pressure of 100.0 torr at the temperature of the solution. The vapor at equilibrium above the solution has double the mole fraction of substance A that the solution does. What is the mole fraction of liquid A in the solution? 117. In some regions of the southwest United States, the water is very hard. For example, in Las Cruces, New Mexico, the tap water contains about 560 g of dissolved solids per milliliter. Reverse osmosis units are marketed in this area to soften water. A typical unit exerts a pressure of 8.0 atm and can produce 45 L water per day. a. Assuming all of the dissolved solids are MgCO, and assum- ing a temperature of 27°C, what total volume of water must be processed to produce 45 L pure water? b. Would the same system work for purifying seawater? (As sume seawater is 0.60 M NaC1.) Integrative Problems hese problems require the integration of multiple concepts to find the

Explanation / Answer

27ºC to K are 27+273, it must be 300 K; this is definitively a typing error. Trust Yourself.

Solve the problem:

PI = MRT

PI = 8 atm ; T = 300 K , R = 0.0082

M = PI/RT = (8)/(0.082*300) = 0.3252 mol per liter

if you need 560 micrograms of dissolved mass then:

mol = mass/MW = (560*10^-6) / 84.3 = 0.000006642941874 mol of MgCO3 (per ml)

therefore

per liter = 0.006642941874 mol

Solve for L

M = mol/L

M = 0.3252

L = mol/M = 0.006642941874/0.3252 = 0.02042725054 L

b)

no,

you will probably need more pressure; since the molarity is too high

NOTE:

report this problem as wrong, in order to be corrected

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