Vapor Pressure Part A What is the boiling point of water at an elevation of 9000

Question

Vapor Pressure

Part A

What is the boiling point of water at an elevation of 9000 ft ?

Express your answer with the appropriate units using three significant figures.

100°C

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Vapor Pressure

The vapor pressure of a substance describes how readily molecules at the surface of the substance enter the gaseous phase. At the boiling point of a liquid, the liquid's vapor pressure is equal to or greater than the atmospheric pressure exerted on the surface of the liquid. Since the atmospheric pressure at higher elevations is lower than at sea level, the boiling point of water decreases as the elevation increases. The atmospheric pressure at sea level is 760 mmHg. This pressure decreases by 19.8 mmHg for every 1000-ft increase in elevation. Elevation Pressure 0 ft 760 mmHg 1000 ft 740.2 mmHg 2000 ft 720.4 mmHg The boiling point of water decreases 0.05C for every 1 mmHg drop in atmospheric pressure.

Part A

What is the boiling point of water at an elevation of 9000 ft ?

Express your answer with the appropriate units using three significant figures.

T =

100°C

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Explanation / Answer

Pressure at 9000 ft = 760 mm Hg - 9 * 19.8 mm Hg = 581.8 mm Hg

Drop in Pressure = 19.8 * 9 = 178.2 mm Hg

For every 1 mm Hg drop im atmospheric pressure, boiling point of water decreases by 0.05C

Decrease in boiling point of water = 178.2 mm Hg * 0.05C/1mm Hg = 8.91

Boiling Point of water = 100 - 8.91 = 91.09C

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