Reaction Rate and Activation Energy Response you wish to us with ozone for which
ID: 981668 • Letter: R
Question
Reaction Rate and Activation Energy Response you wish to us with ozone for which The data below refers to the reaction of hydroperoxyl 2 On 1.0 103 at 25 C) 0.000 2.6.10 2.4 0.030 find k? The rate law for this reaction is rate kpHo2][o]. this make it easier to The concentration oro is much greater than Hoz. How does you wish to create a plot showing a linear relationship between time and the diminishing given data? concentration of [HO2], how do you need to manipulate create your plot in Excel and attach it to this handout. Report the slope of your line here. Calculate k for this reaction.Explanation / Answer
Thee rate law for this reaction is =K [HO2] [O2] when O2 concentration is much higher than HO2, the variation of concentraiton O2 is insignificant with respect to time, the concentration of O2 through out the course of reaction, the reaction can be written as r= K' [HO2] the reaction becomrs pseudo order reaction
The reaction which is originally second order reaction becomes first oder. For first order reaction
ln (1-XA)= K't, where K' is the slope of -ln (1-XA) vs t
XA= CA/CAO, CA= Concentration of O2 at time t and CAO= concentration of O2 at t=0
The data points and the calculations are tabulated.
The data on -ln (1-XA) vs time is calculated and plotted and shown below
The slope is 9.834 /sec which is the value of K'
Time (dec) CAO CA XA t (sec) (-ln(1-XA) 0 0.0000032 0.0000032 0 0 0 0.01 0.0000032 0.0000029 0.09375 0.01 0.09844 0.02 0.0000032 0.0000026 0.1875 0.02 0.207639 0.03 0.0000032 0.0000024 0.25 0.03 0.287682 0.08 0.0000032 0.0000014 0.5625 0.08 0.826679Related Questions
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