Data Table 2: Varying the Concentration of 0.3 M Na2S2O3 ---- C o n c e n t r a
ID: 981160 • Letter: D
Question
Data Table 2: Varying the Concentration of 0.3 M Na2S2O3 ---- C o n c e n t r a t i o n s --- # drops # drops # drops Initial Initial Final Final Reaction Time (sec) Reaction Well # HCl water Na2S2O3 HCl Na2S2O3 HCl Na2S2O3 Trial 1 Trial 2 Average Rate (sec-1) 1 8 0 12 1M 0.3M 0.4M 0.12M 21.88 21.47 21.67 .046 2 8 6 6 1M 0.15 0.7M 0.11M 46.13 41.72 43.92 .022 3 8 8 4 1M 0.1 0.8M 0.08M 85.91 74.09 80 .016 Is this a first order reaction as well? if so with both data tables is my rate law going to be rate=k[HCI]^1[na2s2o3]1??
Explanation / Answer
Please if possible send more data in a systematic way, to help answer the most correct and efficient form.
For one thing it does not understand variable in question belongs each numerical value .
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